A) \[2\times {{10}^{-2}}C\]
B) \[3\times {{10}^{-2}}C\]
C) \[4\times {{10}^{-2}}C\]
D) \[1\times {{10}^{-2}}C\]
Correct Answer: B
Solution :
Charge flows from high potential to low potential \[\frac{K{{Q}_{1}}}{3}=\frac{K{{Q}_{2}}}{1}\] \[{{Q}_{1}}=3{{Q}_{2}}\] Also \[{{Q}_{1}}+{{Q}_{2}}=4\times {{10}^{-2}}\] \[4{{Q}_{2}}=4\times {{10}^{-2}}\] \[{{Q}_{2}}={{10}^{-2}}\] and \[{{Q}_{1}}=3\times {{10}^{-2}}C\]You need to login to perform this action.
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