A) their magnetic behaviour
B) their unfilled d-orbitals
C) their ability to adopt variable oxidation states
D) their chemical reactivity
Correct Answer: C
Solution :
Transition metals show variable oxidation states, due to which they can perform as catalyst. e.g., \[2S{{O}_{2}}+{{O}_{2}}\xrightarrow[(catalyst)]{{{V}_{2}}{{O}_{5}}}2S{{O}_{3}}\] \[S{{O}_{2}}+{{\overset{+5}{\mathop{V}}\,}_{2}}{{O}_{5}}\xrightarrow{{}}S{{O}_{3}}+{{\overset{+4}{\mathop{V}}\,}_{2}}{{O}_{4}}\] \[{{\overset{+4}{\mathop{V}}\,}_{2}}{{O}_{4}}+{{O}_{2}}\xrightarrow{{}}{{\overset{+5}{\mathop{V}}\,}_{2}}{{O}_{5}}\]
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