A) \[\text{425}\text{.5}\,\,\text{S}\,\,\text{c}{{\text{m}}^{\text{2}}}\,\text{mo}{{\text{l}}^{\text{-1}}}\]
B) \[\text{180}\text{.5}\,\,\text{S}\,\,\text{c}{{\text{m}}^{\text{2}}}\,\text{mo}{{\text{l}}^{\text{-1}}}\]
C) \[\text{290}\text{.8}\,\,\text{S}\,\,\text{c}{{\text{m}}^{\text{2}}}\,\text{mo}{{\text{l}}^{\text{-1}}}\]
D) \[\text{390}\text{.5}\,\,\text{S}\,\,\text{c}{{\text{m}}^{\text{2}}}\,\text{mo}{{\text{l}}^{\text{-1}}}\]
Correct Answer: D
Solution :
\[C{{H}_{3}}COONa+HCl\xrightarrow{{}}NaCl+C{{H}_{3}}COOH\] \[91+425.9=126.4+x\] \[\therefore \] \[x=516.9-126.4\] \[=390.5\,\,S\,\,c{{m}^{2}}\,\,mo{{l}^{-1}}\]You need to login to perform this action.
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