A) 3500 Hz
B) 4000 Hz
C) 5000 Hz
D) 3000 Hz
Correct Answer: C
Solution :
From Doppler's shift, we know for this case \[n'=n\left( \frac{v+{{v}_{s}}}{v-{{v}_{s}}} \right)\] \[=1000\left( \frac{330+220}{330-220} \right)\] \[=1000\left( \frac{550}{110} \right)=5000Hz\]You need to login to perform this action.
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