A) \[2\sqrt{\text{3}}\,\text{J}\]
B) \[3\,\text{J}\]
C) \[\sqrt{\text{3}}\,\text{J}\]
D) \[\frac{3}{2}\,\text{J}\]
Correct Answer: B
Solution :
In this case, work done \[W=MB(\cos {{\theta }_{1}}-\cos {{\theta }_{2}})\] \[=MB(\cos {{0}^{o}}-\cos {{60}^{o}})\] \[=MB\left( 1-\frac{1}{2} \right)=\frac{MB}{2}\] \[\text{MB}\,\text{=}\,\text{2}\sqrt{\text{3}}\,\text{J}\]\[(\because \text{given}\,\text{W=}\sqrt{\text{3}}\,\text{J})\] \[\text{ }\!\!\tau\!\!\text{ }\,\text{=}\,\text{MB}\,\text{sin}\,\text{6}{{\text{0}}^{\text{o}}}\text{=}\,\text{(2}\sqrt{\text{3}}\text{)}\left( \frac{\sqrt{\text{3}}}{\text{2}} \right)\text{J}\,\text{=}\,\text{3}\,\text{J}\]You need to login to perform this action.
You will be redirected in
3 sec