A) \[\text{M}\left( \text{N},\text{ Z} \right)=\text{N}{{\text{M}}_{\text{n}}}+\text{Z}{{\text{M}}_{\text{p}}}-\text{B}{{\text{e}}^{\text{2}}}\]
B) \[\text{M}\left( \text{N},\text{Z} \right)=\text{N}{{\text{M}}_{\text{n}}}+\text{Z}{{\text{M}}_{\text{p}}}+\text{B/}{{\text{c}}^{\text{2}}}\]
C) \[\text{M}\left( \text{N},\text{ Z} \right)=\text{N}{{\text{M}}_{\text{n}}}+\text{Z}{{\text{M}}_{\text{p}}}-\text{B}/{{\text{c}}^{\text{2}}}\]
D) \[\text{M}\left( \text{N},\text{ Z} \right)=\text{N}{{\text{M}}_{\text{n}}}+\text{Z}{{\text{M}}_{\text{p}}}+\text{B}/{{\text{c}}^{\text{2}}}\]
Correct Answer: C
Solution :
Binding energy of a nucleus containing N neutrons and Z protons is \[B=[N{{M}_{n}}+Z{{M}_{p}}-M(N,Z)]{{c}^{2}}\] \[\Rightarrow \] \[\frac{B}{{{c}^{2}}}=N{{M}_{n}}+Z{{M}_{p}}-M(N,Z)\] \[\Rightarrow \] \[M(N,Z)=N{{M}_{n}}+Z{{M}_{p}}-B/{{c}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec