A) \[2500\,\Omega \] as a shunt
B) \[245\,\,\Omega \] as shunt
C) \[2550\,\,\Omega \] in series
D) \[2450\,\,\Omega \] in series
Correct Answer: D
Solution :
To convert a galvanometer into voltmeter, high resistance should be connected in series with it. Let R is the resistance connected in series with the galvanometer. Galvanometer current \[{{i}_{g}}=\frac{V}{G+R}\] or\[R=\frac{V}{{{i}_{g}}}-G\] Given,\[G=50\Omega \] \[{{i}_{g}}=25\times 4\times {{10}^{-4}}={{10}^{-2}}A,V=25V\] \[\therefore \]\[R=\frac{25}{{{10}^{-2}}}-50=2500-50=2450\,\Omega \]You need to login to perform this action.
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