A) \[\log \frac{[I{{n}^{-1}}]}{[\text{HIn}]}=p{{k}_{\ln }}-pH\]
B) \[\log \frac{[\text{Hn}]}{[I{{n}^{-}}]}=p{{k}_{In}}-pH\]
C) \[\log \frac{[HIn]}{[I{{n}^{-}}]}=pH-p{{K}_{\ln }}\]
D) \[\log \frac{[I{{n}^{-}}]}{[HIn]}=pH-p{{K}_{In}}\]
Correct Answer: D
Solution :
Acid indicators are generally weak acid. The dissociation of indicator \[Hin\]takes place as follows:You need to login to perform this action.
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