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NEET AIPMT SOLVED PAPER SCREENING 2004

  • question_answer
    The work done during the expansion of a gas from a volume of \[4\,d{{m}^{3}}\]to\[6\,d{{m}^{3}}\]against a constant external pressure of 3 atm, is:                                                                                                                                        

    A) \[-\,\,\text{6}\,\,\text{J}\]                 

    B) \[-\,\,\text{6}0\text{8}\,\,\text{J}\]                               

    C) \[+\text{ 3}0\text{4  J}\]                      

    D) \[-\text{ 3}0\text{4 J}\]

    Correct Answer: B

    Solution :

      Work done (W) \[=-{{P}_{ext}}({{V}_{2}}-{{V}_{1}})\] \[=-3\times (6-4)=-6\,L.\,\,atm\] \[=-6\times 101.32\,J\]\[(\therefore \,1\,\,L\text{-atm=101}\text{.32}\,\text{J})\] \[=-607.92\approx 608\,J\]


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