A) \[\frac{9V}{35}\]
B) \[\frac{5V}{18}\]
C) \[\frac{5V}{9}\]
D) \[\frac{18V}{5}\]
Correct Answer: B
Solution :
The circuit given resembles the balanced Wheatstone Bridge as \[\frac{4}{6}=\frac{2}{3}\] Thus, middle arm containing 4\[\Omega \] resistance will be ineffective and no current flows through it. The equivalent circuit is shown as below:You need to login to perform this action.
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