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NEET AIPMT SOLVED PAPER SCREENING 2005

  • question_answer
                    At a particular locus, frequency of 'A' allele is 0.6 and that of 'a' is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium?                                                   

    A)                 0.16                      

    B)                 0.48                       

    C)                 0.36                       

    D)                 0.24

    Correct Answer: B

    Solution :

                    Allele frequency is the relative proportion of a particular  allele  among  individuals  of a population, According to Hardy-Weinberg equation, the frequency of dominant and recessive alleles in a population will remain constant from generation to generation if there is no mutation, selection, random drift and migration.                 As per Hardy-Weinberg equation                 \[{{p}^{2}}+2pq+{{q}^{2}}=1\]                 p = dominant allele frequency                 q = recessive allele frequency                 \[{{p}^{2}}=\] homozygous dominant genotype                 2pq = heterozygous genotype                 \[{{q}^{2}}=\] homozygous recessive genotype                 In question p = 0.6 and q = 0.4                 Therefore, heterozygotes frequency is                 \[=2pq\,=2\times 0.6\times 0.4=0.48\].


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