A) 3 Hz
B) 2 Hz
C) 4 Hz
D) 1 Hz
Correct Answer: D
Solution :
Maximum speed of a particle executing SHM is \[{{u}_{\max }}=a\,\omega \,=a\,(2\pi n)\] \[\Rightarrow n=\frac{{{u}_{\max }}}{2\pi a}\] Here, \[{{u}_{\max }}\] = 31.4 cm/s, a= 5cm Substituting, the given values, we have \[n=\frac{31.4}{2\times 3.14\times 5}=1\,Hz\]
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