A) 180 kg
B) 270 kg
C) 540 kg
D) 90 kg
Correct Answer: D
Solution :
In hall and Heroult process \[2A{{l}_{2}}{{O}_{3}}\xrightarrow[{}]{{}}4Al+3{{O}_{2}}\] \[4C+3{{O}_{2}}\xrightarrow[{}]{{}}2C{{O}_{2}}+2CO\uparrow \] \[2A{{l}_{2}}{{O}_{3}}+4C\xrightarrow[{}]{{}}4aL+2C{{O}_{2}}+2CO\] Only for removal of \[C{{O}_{2}},\] following equation is possible \[2A{{l}_{2}}{{O}_{3}}+\underset{3\times 12=36}{\mathop{3C}}\,\,\xrightarrow[{}]{{}}\,\underset{4\times 27=108}{\mathop{4Al}}\,\times 3C{{O}_{2}}\] \[\because \] For 108 g of Al, 36 g of C is required in above reaction. \[\therefore \] For 270 g of Al required amount of C \[=\frac{36}{108}\times 270=90\,g\]
You need to login to perform this action.
You will be redirected in
3 sec
