A) QV
B) zero
C) 2 QV
D) QV/2
Correct Answer: A
Solution :
Induced emf work done in taking a charge \[=\frac{Q\,\,once\,along\,the\,loop}{ch\arg e\,Q}\] i.e., \[V=\frac{W}{Q}\] \[\Rightarrow W=VQ\]You need to login to perform this action.
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