A) \[-41\,\,kJ\,mo{{l}^{-1}}\]
B) \[-1312\,kJ\,mo{{l}^{-1}}\]
C) \[-164\,kJ\,mo{{l}^{-1}}\]
D) \[-82\,kJ\,mo{{l}^{-1}}\]
Correct Answer: B
Solution :
The energy of second Bohr orbit of hydrogen atom \[({{E}_{2}})\] is \[-328\,kJ\,mo{{l}^{-1}}\] because \[{{E}_{2}}=-\frac{1312}{{{2}^{2}}}\,kJ\,mo{{l}^{-1}}\] \[\therefore {{E}_{n}}=\frac{1312}{{{n}^{2}}}kJ\,mo{{l}^{-1}}\] If n = 4 \[\therefore \,\,\,{{E}_{4}}=-\frac{1312}{{{n}^{2}}}kJ\,mo{{l}^{-1}}\,=-82\,kJ\,mo{{l}^{-1}}\]
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