A) \[N{{i}^{2+}},\,T{{i}^{3+}}\] \[_{28}Ni=1{{s}^{2}},2{{s}^{2}}\,2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{8}},4{{s}^{2}}\] \[N{{i}^{2+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{{}}}\] \[_{22}Ti=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{2}},4{{s}^{2}}\] \[T{{i}^{3+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{1}}\] \[_{21}Sc=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{1}},4{{s}^{2}}\] \[S{{c}^{3+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}\] (unpaired electron in d-orbital is not possible) \[_{29}Cu=1{{s}^{2}},2{{s}^{2}}\,2{{p}^{6}},3{{s}^{2}}\,3{{p}^{6}}\,3{{d}^{10}},4{{s}^{1}}\] \[C{{u}^{+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{10}}\] (complete d-orbital) Hence, in above ions, \[N{{i}^{2+}}\] and \[T{{i}^{3+}}\] ions are coloured ions in aqueous solution due to presence of unpaired electrons in d-sub-shell.
B) \[S{{c}^{3+}},\,T{{i}^{3+}}\]
C) \[S{{c}^{3}},\,C{{o}^{2+}}\]
D) \[N{{i}^{2+}},\,C{{u}^{+}}\] (At. no.: Sc = 21, Ti = 22, Ni = 28, Cu = 29, Co = 27)
Correct Answer: A
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