A) \[C{{H}_{3}}OH+{{(C{{H}_{3}})}_{2}}CHI\]
B) \[IC{{H}_{2}}OCH{{(C{{H}_{3}})}_{2}}\]
C) \[C{{H}_{3}}O\,\,\underset{\begin{smallmatrix} | \\ I \end{smallmatrix}}{\mathop{C}}\,{{(C{{H}_{3}})}_{2}}\]
D) \[C{{H}_{3}}I+{{(C{{H}_{3}})}_{2}}CHOH\]
Correct Answer: D
Solution :
In case of unsymmertical ether, the alkyl halide is always formed from smaller alkyl group. This happen so, because \[{{I}^{-}}\] ion being larger in size approaches smaller alkyl group to avoid steric hindrance.You need to login to perform this action.
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