A) -121 kJ per mol
B) +121 kJ per mol
C) +242 kJ per mol
D) -242 kJ per mol
Correct Answer: A
Solution :
\[\Delta H=\] [\[\Delta H\]of combustion of cyclohexane - (\[\Delta H\] of combustion of cyclohexene +\[\Delta H\]of combustion of H2)] \[=-[-3920-(3800-24)]\,kJ\] \[=-[3920+4041]\,kJ\] = -[121] kJ = -121 kJYou need to login to perform this action.
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