A) \[290\,kJ\,mo{{l}^{-1}}\]
B) \[380\,kJ\,mo{{l}^{-1}}\]
C) \[425\,kJ\,mo{{l}^{-1}}\]
D) \[245\,kJ\,mo{{l}^{-1}}\]
Correct Answer: B
Solution :
\[\Delta {{H}_{reaction}}={{\Delta }_{H-H}}+\Delta {{H}_{Cl-Cl}}-2\Delta {{H}_{HCl}}=-90\,kJ\] \[or\Delta {{H}_{H-Cl}}=\frac{430+240-(-90)}{2}\] \[=\frac{760}{2}=380\,kJ\,mo{{l}^{-1}}\]You need to login to perform this action.
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