NEET AIPMT SOLVED PAPER SCREENING 2007

  • question_answer
                    The frequency of a light wave in a material is \[2\times {{10}^{14}}Hz\] and wavelength is \[5000\overset{\text{o}}{\mathop{\text{A}}}\,\]. The refractive index of material will be:                                                                                                                                                           

    A)                  1.40      

    B)                  1.50                      

    C)                  3.00      

    D)                  1.33

    Correct Answer: C

    Solution :

                              Velocity of light waves in material is                 \[v-v\lambda \]                                ....(i)                 Refractive index of material is                 \[\mu =\frac{c}{v}\]                                        ?(ii)                 where c is speed of light in vacuum or air. or            \[\mu =\frac{c}{v\lambda }\]                                      ...(iii) Given,   \[v=2\times {{10}^{14}}\,Hz,\]                 \[\lambda =5000\,{\AA}=5000\,\times {{10}^{-10}}\,m,\]                 \[c=3\times {{10}^{8}}\,m/s\]                 Hence, from Eq. (iii), we get                 \[\mu =\frac{3\times {{10}^{8}}}{2\times {{10}^{14}}\times 5000\times {{10}^{-10}}}\,=3.00\]


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