A) \[20\,\,\Omega \]
B) \[2\,\,\Omega \]
C) \[0.2\,\,\Omega \]
D) \[2\,k\,\,\Omega \]
Correct Answer: B
Solution :
Key Idea: The potential difference across ammeter and shunt is same. Let \[{{i}_{a}}\] is the current flowing through ammeter and i is the total current. So, a current! \[-{{i}_{a}}\] will flow through shunt resistance. Potential difference across ammeter and shunt resistance is same. \[i.e.,{{i}_{a}}\times R=(i-{{i}_{a}})\times S\] \[orS=\frac{{{i}_{a}}R}{i-{{i}_{a}}}....(i)\] Given, \[{{i}_{a}}=100\,A,\,\,i=750\,A,R=13\,\Omega \] Hence, \[S=\frac{100\times 13}{750-100}=2\,\Omega \]You need to login to perform this action.
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