A) \[\frac{qQ}{4\pi {{\varepsilon }_{0}}L}\]
B) \[\frac{qQ}{2\pi {{\varepsilon }_{0}}L}\]
C) \[\frac{qQ}{6\pi {{\varepsilon }_{0}}L}\]
D) \[-\frac{qQ}{6\pi {{\varepsilon }_{0}}L}\]
Correct Answer: D
Solution :
Key Idea: Work done is equal to change ii potential energy. In Ist case, when charge +Q is situated at C.You need to login to perform this action.
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