A) 11.10 mL
B) 16.65 mL
C) 22.20 mL
D) 5.55 Ml
Correct Answer: D
Solution :
Normality = \[\frac{wt%\,\times \,density\,\times 10}{eq.wt.}\] \[=\frac{98\times 1.8\times 10}{49}=36\,N\] \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[36\times V=0.2\times 1000\] \[V=\frac{0.2\times 1000}{36}=5.55\,ml.\]You need to login to perform this action.
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