A) \[C{{r}^{3+}}\]
B) \[{{V}^{3+}}\]
C) \[T{{i}^{3+}}\]
D) Mn3+ (At. no. Ti = 22, V - 23, Cr = 24, Mn = 25)
Correct Answer: C
Solution :
Stability of transition metal ion is directly proportional to the unpaired electron. The exactly half filled and completely filled d-orbirals are extra stable. \[C{{r}^{3+}}(21)=3{{d}^{3}}4{{s}^{0}}-3\] unpaired electrons \[{{V}^{3+}}(20)=3{{d}^{2}}\,4{{s}^{0}}-2\] unpaired electrons \[T{{i}^{3+}}(19)=3{{d}^{1}}4{{s}^{0}}-1\] unpaired electron \[M{{n}^{3+}}(22)\,=3{{d}^{4}}\,4{{s}^{0}}\,-4\] unpaired electrons So, \[M{{n}^{3+}}\] ion is most stable in aqueous solution.
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