A) \[C{{a}^{2+}}<{{K}^{+}}<Ar<{{S}^{2-}}<C{{l}^{-}}\]
B) \[C{{a}^{2+}}<{{K}^{+}}<Ar<C{{l}^{-}}<{{S}^{2-}}\]
C) \[Ar<C{{a}^{2+}}<{{K}^{+}}<C{{l}^{-}}<{{S}^{2-}}\]
D) \[C{{a}^{2+}}<Ar<{{K}^{+}}<C{{l}^{-}}<{{S}^{2-}}\]
Correct Answer: B
Solution :
A cation has always the lesser ionic size than a metal atom due to loss of electron and an anion has always the greater size than metal atom due to gain of electrons. So, the correct order of size is as \[C{{a}^{2+}}<{{K}^{+}}<Ar<C{{l}^{-}}<{{S}^{2-}}\]
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