NEET AIPMT SOLVED PAPER SCREENING 2008

  • question_answer
    If uncertainty in position and momentum are equal, then uncertainty in velocity is

    A) \[\frac{1}{2m}\sqrt{\frac{h}{\pi }}\]

    B)                        \[\sqrt{\frac{h}{2\pi }}\]

    C) \[\frac{1}{m}\sqrt{\frac{h}{\pi }}\]          

    D)        \[\sqrt{\frac{h}{\pi }}\]

    Correct Answer: A

    Solution :

    Key Idea: According to Heisenberg's uncertainty principle, it is impossible to determine simultaneously the position and momentum of c moving microscopic particle, ie, \[\Delta x\times \Delta p\ge \frac{h}{4\pi }\]\[\because \]\[\Delta x\times \Delta p\ge \frac{h}{4\pi }\] Here \[\Delta x=\Delta p\]and\[\Delta p=m.\Delta v\] \[\therefore \]\[\Delta {{v}^{2}}=\frac{h}{{{m}^{2}}4\pi }\]or\[\Delta v=\frac{1}{2m}\sqrt{\frac{h}{\pi }}\] Note: The uncertainty principle, in terms of energy and time is given as \[\Delta E.\Delta t\ge \frac{h}{4\pi }\]


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