A) 3.4 eV
B) 6.8 eV
C) 10.2 eV
D) zero
Correct Answer: C
Solution :
Key Idea: Excitation energy is defined as the energy required to take the electron from ground level orbit to any higher order orbit (ie, n = 2, 3, 4...). Given, ground state energy of hydrogen atom \[{{E}_{1}}=-13.6eV\] Energy of electron in first excited state (ie, n = 2)\[{{E}_{2}}=-\frac{13.6}{{{(2)}^{2}}}eV\] Therefore, excitation energy \[\Delta E={{E}_{2}}-{{E}_{1}}\] \[=-\frac{13.6}{4}-(-13.6)\] \[=-3.4+13.6=10.2eV\]
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