NEET AIPMT SOLVED PAPER SCREENING 2009

  • question_answer
    A body of mass 1 kg is thrown upwards with a velocity 20 \[\overrightarrow{F}.\overrightarrow{\tau }=0\]. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? \[\text{m}{{\text{s}}^{-1}}\]

    A) 20 J

    B)                                        30 J

    C) 40 J                                        

    D) 10 J

    Correct Answer: A

    Solution :

    Key Idea The energy lost due to air friction is equal to difference of initial kinetic energy and final potential energy. Initially body posses only kinetic energy and after attaining a height the kinetic energy is zero. Therefore, loss of energy = KE - PE \[\text{-}\] \[=\frac{1}{2}\times 1\times 400-1\times 18\times 10\] \[_{Z}^{A}X\xrightarrow[{}]{{}}{{\,}_{Z+}}_{1}^{A}Y+\beta _{-1}^{0}\]


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