A) \[y=(0.02)m\sin (15.7x-2010t)\]
B) \[y=(0.02)m\sin (15.7x+2010t)\]
C) \[y=(0.02)m\sin (7.85x+1005t)\]
D) \[x=\frac{a}{2}\]
Correct Answer: B
Solution :
Key Idea Apply law of conservation of angular momentum. \[\lambda =\frac{hc}{E}\] In the given case \[{{I}_{1}}=M{{R}^{2}}\] \[4000{\AA}<5000{\AA}\] \[=\frac{1}{2}m{{v}^{2}}-mgh\] Then\[=\frac{1}{2}\times 1\times 400-1\times 10\times 10\]You need to login to perform this action.
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