2. Solved Papers
  3. NEET

NEET AIPMT SOLVED PAPER SCREENING 2009

  • question_answer
    A thin circular ring of mass M and radius R is rotating in a horizontal plane about an axis vertical to its plane with a constant angular velocity \[\omega \]. If two objects each of mass m be attached gently to the opposite ends of a diameter of the ring, the ring will then rotate with an angular velocity

    A) \[y=(0.02)m\sin (15.7x-2010t)\]

    B)        \[y=(0.02)m\sin (15.7x+2010t)\]               

    C)        \[y=(0.02)m\sin (7.85x+1005t)\]               

    D)        \[x=\frac{a}{2}\]

    Correct Answer: B

    Solution :

    Key Idea Apply law of conservation of angular momentum. \[\lambda =\frac{hc}{E}\] In the given case \[{{I}_{1}}=M{{R}^{2}}\] \[4000{\AA}<5000{\AA}\] \[=\frac{1}{2}m{{v}^{2}}-mgh\] Then\[=\frac{1}{2}\times 1\times 400-1\times 10\times 10\]


You need to login to perform this action.
You will be redirected in 3 sec spinner