NEET AIPMT SOLVED PAPER SCREENING 2009

  • question_answer
    A student measures the terminal potential difference (V) of a cell (of emf s and internal resistance r) as a function of the current (I) flowing through it. The slope and intercept of the graph between V and I, then respectively, equal

    A) \[m{{s}^{-1}}\] and - r      

    B)        - r and \[(g=10m{{s}^{-2}})\]      

    C)                        r and -\[\vec{F}\]       

    D)        -\[\overrightarrow{r}\] and r

    Correct Answer: B

    Solution :

    According to Ohm's law \[4.8\pi \mu V\] and\[0.8\pi \mu V\]if \[1.6\pi \mu V\]   \[{{M}^{a}}{{L}^{b}}{{T}^{c}},\] \[a=1,b=-1,c=-2\]Slope of the graph = - r and intercept \[a=1,b=0,c=-1\]


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