NEET AIPMT SOLVED PAPER SCREENING 2009

  • question_answer
    Two bodies of mass 1 kg and 3 kg have position vectors \[\overrightarrow{\tau }\]and \[\overrightarrow{r}.\overrightarrow{\tau }\ne 0\]respectively. The centre of mass of this system has a position vector

    A) \[\overrightarrow{F}.\overrightarrow{\tau }=0\]             

    B)        \[\overrightarrow{r}.\overrightarrow{\tau }>0\]              

    C)        \[\overrightarrow{F}.\overrightarrow{\tau }<0\]             

    D)        \[-\hat{i}+\hat{j}+\hat{k}\]

    Correct Answer: B

    Solution :

    The position vector of centre of mass \[a=1,b=1,c=-2\] \[a=0,b=-1,c=-2\] \[_{Z}^{A}Z\xrightarrow[{}]{{}}{{\,}_{Z+}}_{1}^{4}Y\xrightarrow[{}]{{}}\,_{Z-1}^{A-4}{{B}^{*}}\xrightarrow[{}]{{}}\,_{Z-1}^{A-4}B,\] \[\beta ,\alpha ,\gamma \] The centre of mass changes its position only under the translatory motion. There is no effect of rotatory motion on centre of mass of the body.


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