NEET AIPMT SOLVED PAPER SCREENING 2009

  • question_answer
    The internal energy change in a system that has absorbed 2 kcal of heat and done 500 J of work is

    A) 8900 J 

    B)                                        6400 J   

    C)        5400 J                   

    D)        7900 J

    Correct Answer: D

    Solution :

    Key Idea Heat given to a system \[\gamma ,\beta ,\alpha \]is equal to the sum of increase in the internal energy \[\beta ,\gamma ,\alpha \]and the work done \[\alpha ,\beta ,\gamma \] by the system against the surrounding and 1 cat = 4.2 J. According to first law of thermodynamics \[\sigma ,-\sigma \] \[\sigma \] \[{{V}_{A}},{{V}_{B}}\] \[{{V}_{C}}\]


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