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NEET AIPMT SOLVED PAPER SCREENING 2009

  • question_answer
    In a Rutherford scattering experiment when a projectile of charge\[4m{{s}^{-2}}\]and mass\[14m{{s}^{-2}}\] approaches a target nucleus of charge \[\overrightarrow{v}=v\hat{i}.\] and mass \[{{s}_{1}}\]the distance of closest approach is \[{{s}_{2}}\]. The energy of the projectile is

    A) directly proportional to\[{{s}_{2}}=2{{s}_{1}}\]

    B) directly proportional to \[{{s}_{2}}=3{{s}_{1}}\]

    C) inversely proportional to \[{{s}_{2}}=4{{s}_{1}}\]

    D) directly proportional to mass \[{{s}_{2}}={{s}_{1}}\]

    Correct Answer: B

    Solution :

    A particle of mass \[\text{40m}{{\text{s}}^{-1}}\] and charge \[\text{25m}{{\text{s}}^{-1}}\] possess initial velocity u, when it is at, a large distance from the nucleus of an atom having atomic number \[\text{10m}{{\text{s}}^{-1}}\]At the distance of closest approach, the kinetic energy of particle is completely converted to potential energy. Mathematically,\[\text{m}{{\text{s}}^{-1}}\] So the energy of the particle is directly proportional to \[y=(0.02)m\sin (7.85x+1005t)\]


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