NEET AIPMT SOLVED PAPER SCREENING 2009

  • question_answer
    If the dimensions of a physical quantity are given by \[{{v}_{s}}=10+10=20m{{s}^{-}}^{1}\]then the physical quantity will be

    A) pressure if\[T=\frac{2\pi r}{v}=\frac{2\pi }{v}\times \frac{mv}{Bq}\]

    B) velocity if \[T=\frac{2\pi m}{Bq}\]

    C) acceleration if \[v=128\,\text{m}{{\text{s}}^{-1}}\]

    D) force if \[5\lambda =4\]

    Correct Answer: A

    Solution :

    (i) Dimensions of velocity \[n=3,l=2,m=-2,s=-1/2\] Here, a = 0, b = 1, c = -1 (ii) Dimensions of acceleration\[C{{H}_{2}}Br-CHBr-COOH\] Here, a = 0, b = 1, c = - 2 (iii) Dimensions of force \[H-\underset{\begin{smallmatrix}  | \\  Br \end{smallmatrix}}{\overset{\begin{smallmatrix}  Br \\  | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{2}}COOH\] Here, a = 1, b = 1, r = - 2 (iv) Dimensions of pressure \[C{{H}_{2}}Br-C{{H}_{2}}-COBr\] \[C{{H}_{3}}-\underset{\begin{smallmatrix}  | \\  Br \end{smallmatrix}}{\overset{\begin{smallmatrix}  Br \\  | \end{smallmatrix}}{\mathop{C}}}\,-COOH\]Here;    a = 1, b = - 1, c = - 2 \[\to \]The physical quantity is pressure.


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