A) \[v=\frac{\omega }{k}=128\,\text{m}{{\text{s}}^{-1}}\]
B) \[\Rightarrow \]
C) \[\omega =v\times k=128\times 7.85\]
D) \[y=A\sin (kx-\omega t)\]
Correct Answer: A
Solution :
Key Idea In a nuclear reaction conservation of charge number and mass number must hold good. Alpha particles are positively charged particles with charge +2e and mass 4 m. Emission of an \[\to \]particle reduces the mass of the radionuclide by 4 and its atomic number by 2. \[\to \]particles are negatively charged particles with rest mass as well as charge same as that of electrons. \[\to \]particles carry no charge and mass. Radioactive transition will be as follows \[\to \] \[\to \] \[\to \]
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