A) \[\frac{V}{3},3V\]
B) \[3C,3V\]
C) \[-2\mu C\]
D) \[(2\hat{i}+3\hat{j})\times {{10}^{6}}m{{s}^{-1}}\]
Correct Answer: D
Solution :
Energy =2eV \[\frac{\omega M}{M+2m}\] \[\frac{\omega (M+2m)}{M}\]\[\frac{\omega M}{M+m}\] Now, electric field \[{{V}_{c}}=2\] \[\text{A}\] \[\text{A}\]
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