A) n = 3 to n = 2 states
B) n = 3 to n = 1 states
C) n = 2 to n = 1 states
D) n =4 to n = 3. states
Correct Answer: D
Solution :
Key Idea Number of spectral lines obtained due to transition of electron from \[-3\hat{i}-2\hat{j}+\hat{k},\]orbit to lower orbit \[-2\hat{i}+2\hat{k}\] and for maximum wavelength the difference between the orbits of the series should be minimum. Number of spectral lines \[-2\hat{i}-\hat{j}+\hat{k}\] \[2\hat{i}-\hat{j}-2\hat{k}\]\[\frac{1}{2}m{{v}^{3}}\]or\[m{{v}^{3}}\] or\[\frac{1}{2}m{{v}^{2}}\]or\[\frac{1}{2}{{m}^{2}}{{v}^{2}}\] Now as the first line of the series has the maximum wavelength, therefore electron jumps from the 4th orbit to the third orbit.
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