A) \[V{{m}^{-1}}\]
B) \[8\times {{10}^{7}}\]
C) \[5\times {{10}^{-11}}\]
D) \[8\times {{10}^{-11}}\]
Correct Answer: A
Solution :
Given, \[\frac{dQ}{dt}\] \[\frac{dQ}{dt}=\frac{KL({{T}_{1}}-{{T}_{2}})}{A}\] \[\frac{dQ}{dt}=\frac{K({{T}_{1}}-{{T}_{2}})}{LA}\] ?(i) Hydrolysis of \[N{{H}_{4}}Cl\] takes place as, \[\frac{dQ}{dt}=KLA({{T}_{1}}-{{T}_{2}})\] or\[\frac{dQ}{dt}=\frac{KA({{T}_{1}}-{{T}_{2}})}{L}\] Hydrolysis constant, \[{{\varepsilon }_{1}}-({{i}_{1}}+{{i}_{2}})R-{{i}_{1}}{{r}_{1}}=0\]?(ii) or\[{{\varepsilon }_{2}}-{{i}_{2}}{{r}_{2}}-{{\varepsilon }_{1}}-{{i}_{1}}{{r}_{1}}=0\] From Eqs (i) and (hi) \[-{{\varepsilon }_{2}}-({{i}_{1}}+{{i}_{2}})R+{{i}_{2}}{{r}_{2}}=0\]\[{{\varepsilon }_{1}}-({{i}_{1}}+{{i}_{2}})R+{{i}_{2}}{{r}_{2}}=0\] \[4\times {{10}^{-8}}m.\] \[V{{m}^{-1}}\]
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