NEET AIPMT SOLVED PAPER SCREENING 2009

  • question_answer
    \[\frac{1}{3}M{{l}^{2}}\]is reduced by electrolysis at low potentials and high currents. If \[\text{p}{{\text{V}}^{}}\] A of current is passed through molten \[{{t}_{1}}\] for 6 h, what mass of aluminium is produced ? (Assume 100% current efficiency, at. mass of \[{{t}_{2}}\])

    A) \[{{t}_{1}}>{{t}_{2}}\]    

    B)        \[{{t}_{1}}=4{{t}_{2}}\]                 

    C) \[{{t}_{1}}=2{{t}_{2}}\] 

    D)        \[{{t}_{1}}={{t}_{2}}\]

    Correct Answer: B

    Solution :

    \[\text{v-}{{\text{v}}_{\text{0}}}\] ionises as, \[\text{(}{{\text{v}}_{\text{0}}})\] At cathode \[\text{1g}{{\text{m}}^{\text{-1}}}.\] \[\frac{4}{3}M{{l}^{2}}\]Mass of aluminium deposited by 3 F of electricity = 27 g \[\frac{2}{3}M{{l}^{2}}\]Mass of aluminium deposited by \[\frac{13}{3}M{{l}^{2}}\]of electricity \[\frac{1}{3}M{{l}^{2}}\] \[\text{p}{{\text{V}}^{}}\] \[{{t}_{1}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner