A) 128
B) 157
C) 181
D) 198
Correct Answer: A
Solution :
In case of face-centred cubic lattice, radius \[\text{mo}{{\text{l}}^{\text{-1}}}\] \[\text{mo}{{\text{l}}^{\text{-1}}}\]Radius of copper atom (fee lattice) \[\text{mo}{{\text{l}}^{\text{-1}}}\]
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