A) 5kg
B) 7kg
C) 17kg
D) 3kg
Correct Answer: A
Solution :
Key Idea Apply law of conservation of linear momentum. Momentum of first part \[Ga<In<Al<tl\] Momentum of the second part \[\text{ethanol}\xrightarrow[{}]{\text{PB}{{\text{r}}_{\text{3}}}}\text{X}\xrightarrow[{}]{\text{alc}\text{.KOH}}\text{Y}\] \[\xrightarrow[\text{(ii)}{{\text{H}}_{\text{2}}}\text{O,heat}]{\text{(i)}{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{room}\,\text{temperature}}Z;\]Resultant momentum \[C{{H}_{2}}=C{{H}_{2}}\] The third part should also have the same momentum. Let the mass of the third part be M, then \[C{{H}_{3}}C{{H}_{2}}-O-C{{H}_{2}}-C{{H}_{3}}\] \[C{{H}_{3}}-C{{H}_{2}}-O-S{{O}_{3}}H\] Alternative: \[C{{H}_{3}}C{{H}_{2}}OH\] \[Co{{(N{{H}_{3}})}_{5}}(N{{O}_{2}})Cl\] \[({{k}_{f}}=-{{1.86}^{o}}C/m)\] \[C{{H}_{3}}OH\]You need to login to perform this action.
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