A) \[B=6\times {{10}^{4}}T\]
B) \[60\Omega \]
C) \[240\,\Omega \]
D) \[15\,\Omega \]
Correct Answer: A
Solution :
Key Idea According to Lewis concept, "Acids are electron acceptor and bases are electron donor". Since, electron deficient compounds also have an ability to accept electrons, these are regarded as acids. \[\frac{{{\varepsilon }^{2}}R}{\left[ {{R}^{2}}+{{\left( L\omega -\frac{1}{C\omega } \right)}^{2}} \right]}\] \[\frac{{{\varepsilon }^{2}}\sqrt{{{R}^{2}}+{{\left( L\omega -\frac{1}{C\omega } \right)}^{2}}}}{R}\] \[\frac{{{\varepsilon }^{2}}\left[ {{R}^{2}}+{{\left( L\omega -\frac{1}{C\omega } \right)}^{2}} \right]}{R}\] \[\frac{{{\varepsilon }^{2}}R}{\sqrt{{{R}^{2}}+{{\left( L\omega -\frac{1}{C\omega } \right)}^{2}}}}\]You need to login to perform this action.
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