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NEET AIPMT SOLVED PAPER SCREENING 2009

  • question_answer
    What is the \[0.0\times {{10}^{-2}}{{s}^{-1}}\]in the final solution prepared by mixing 20.0 mL of 0.050 M HCl with 30.0 mL of 0.10 M \[Phenol\xrightarrow[{}]{Zn\,dust}X\xrightarrow[Anhydrous\,AlC{{l}_{3}}]{C{{H}_{3}}Cl}Y\xrightarrow[{}]{\begin{smallmatrix}  Alkaline \\  KMn{{O}_{4}} \end{smallmatrix}}Z,\]?

    A)  0.10 M                

    B)        0.40 M 

    C)        0.0050 M      

    D)        0.12 M

    Correct Answer: A

    Solution :

    Number of mill equivalents of HCl \[CoF_{6}^{3-}\] Number of milliequivalents of \[NiCl_{4}^{2-}\] \[[Ne]3{{s}^{2}}3{{p}^{3}}\]\[[Ne]3{{s}^{2}}3{{p}^{3}}\] of final solution \[[Ar]3{{d}^{10}},4{{s}^{2}}4{{p}^{3}}\] \[[Ne]3{{s}^{2}}3{{s}^{2}}3{{p}^{1}}\]


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