A) \[=\frac{1}{2}\times 1\times 400-1\times 10\times 10\]
B) \[=200-180=20\,\text{J}\]
C) \[\overrightarrow{r}\]
D) \[\overrightarrow{F}.\]
Correct Answer: D
Solution :
Key Idea Find the parameters and put in the general wave equation. Here, A = 2cm direction = +ve x direction \[\therefore \]and\[=\sqrt{{{(12)}^{2}}+{{(16)}^{2}}}=20\text{kg}\,\text{m}{{\text{s}}^{-1}}\] Now,\[4\times M=20\]and\[M=5kg\]\[Mv\cos \theta =12\]\[Mv\sin \theta =16\] = 1005 As,\[\tan \theta =\frac{16}{12}=\frac{4}{3}\] \[M=\frac{12\times 5}{4\times 3}=\frac{60}{12}=5kg\]\[\frac{-dr}{dt}=2mm{{s}^{-1}}\] \[e=\frac{-d\phi }{dt}=\frac{-BdA}{dt}=-B\frac{d(\pi {{r}^{2}})}{dt}\]
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