A) \[{{E}^{o}}=0.153V\]
B) \[Cu+{{e}^{-}}\xrightarrow[{}]{{}}Cu,\]
C) \[{{N}_{2}}+3{{H}_{2}}\xrightarrow[{}]{{}}2N{{H}_{3}},\]
D) \[\frac{d[N{{H}_{3}}]}{dt}=2\times {{10}^{-4}}\]
Correct Answer: D
Solution :
Given, \[2.0\times {{10}^{-19}}J\] \[4.0\times {{10}^{-20}}J\] ?(i) \[{{(C{{H}_{3}})}_{3}}SiCl\]\[C{{H}_{3}}SiC{{l}_{3}}\] ?(ii) \[{{(C{{H}_{3}})}_{4}}Si\]\[{{(C{{H}_{3}})}_{2}}SiC{{l}_{2}}\] On substracting Eq. (ii) from Eq. (i), we get \[Al<Ga<In<Tl\] \[Tl<In<Ga<Al\] White adding two equations, dissociation constants are multiplied and when subtracting the equations, dissociation constants are divided. Alternative \[In<Tl<Ga<Al\]\[Ga<In<Al<tl\] \[\text{ethanol}\xrightarrow[{}]{\text{PB}{{\text{r}}_{\text{3}}}}\text{X}\xrightarrow[{}]{\text{alc}\text{.KOH}}\text{Y}\] ?(i) \[\xrightarrow[\text{(ii)}{{\text{H}}_{\text{2}}}\text{O,heat}]{\text{(i)}{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{room}\,\text{temperature}}Z;\] \[C{{H}_{2}}=C{{H}_{2}}\] ?(ii) \[C{{H}_{3}}C{{H}_{2}}-O-C{{H}_{2}}-C{{H}_{3}}\] \[C{{H}_{3}}-C{{H}_{2}}-O-S{{O}_{3}}H\] ?(iii) From Eqs. (i), (ii) and (iii), \[C{{H}_{3}}C{{H}_{2}}OH\]
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