A) \[Ti=22,co=27,Cu=29,Ni=28\]and\[TiF_{6}^{2-}\]
B) \[CoF_{6}^{3-}\]and\[C{{u}_{2}}C{{l}_{2}}\]
C) \[NO_{2}^{-}\] and\[TiF_{6}^{2-}\]
D) \[C{{u}_{2}}C{{l}_{2}}\]and\[CoF_{6}^{3-}\]
Correct Answer: D
Solution :
Key Idea For \[\to \]hybridisation, there must be either \[\to \]bonds or \[\to \]bonds and one lone pair of electrons in the molecule or ions. \[\to \]bonds, ie, \[\to \]hybridisation \[\to \]bonds +1 lone pair of electrons ie, \[\to \]hybridisation \[\to \] bonds +2 lone pairs, ie, \[\to \]hybridisation \[\to \]bonds +2 lone pairs, ie, \[\to \]hybridisation Thus, in \[\to \]and \[\to \]central atom is sp2 hybridised.You need to login to perform this action.
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