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NEET AIPMT SOLVED PAPER SCREENING 2009

  • question_answer
    A 0.0020 m aqueous solution .of an ionic compound \[3.0\times {{10}^{-5}}\] freezes at 0.00732° C. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be \[3.0\times {{10}^{-4}}\]

    A) 2            

    B)        3             

    C)                        4            

    D)        1

    Correct Answer: A

    Solution :

    Given, molality,\[=[{{M}^{1}}{{L}^{1}}{{T}^{-2}}]\] \[=[{{M}^{1}}{{L}^{1}}{{T}^{-2}}]\] \[\therefore \] \[\therefore \] \[\text{-}\] \[\text{-}\]         \[\text{-}\] Since, the compound is ionic, so number of moles produced is equal to vant' Hoff factor, i. Hence, 2 moles of ions are produced. \[_{Z}^{A}X\xrightarrow[{}]{{}}{{\,}_{Z+}}_{1}^{A}Y+\beta _{-1}^{0}\]


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