A) reducing agent
B) acid
C) base
D) catalyst
Correct Answer: C
Solution :
Key Idea Proton donor are acids and proton acceptor are bases. Cone. \[Co{{(N{{H}_{3}})}_{5}}(N{{O}_{2}})Cl\] and cone. \[({{k}_{f}}=-{{1.86}^{o}}C/m)\] react in the following manner: \[C{{H}_{3}}OH\] \[C{{H}_{3}}Cl\] Hence, in this reaction \[AlC{{l}_{3}}\]acts as a base and \[n=4,l=0,m=0,s=-1/2\]as an acid.You need to login to perform this action.
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