A) T
B) \[T/\sqrt{2}\]
C) 2 T
D) \[\sqrt{2}T\]
Correct Answer: D
Solution :
Time period of spring pendulum, \[T=2\pi \sqrt{\frac{M}{k}}.\] If now mass in doubled \[T'=2\pi \sqrt{\frac{2M}{k}}=\sqrt{2}T\]
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